2+4sin^2(2x)=5

Solution for 2+4sin^2(2x)=5 equation:

Simplifying
2 + 4sin2(2x) = 5

Remove parenthesis around (2x)
2 + 4in2s * 2x = 5

Reorder the terms for easier multiplication:
2 + 4 * 2in2s * x = 5

Multiply 4 * 2
2 + 8in2s * x = 5

Multiply in2s * x
2 + 8in2sx = 5

Solving
2 + 8in2sx = 5

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 8in2sx = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 8in2sx = 5 + -2
8in2sx = 5 + -2

Combine like terms: 5 + -2 = 3
8in2sx = 3

Divide each side by '8n2sx'.
i = 0.375n-2s-1x-1

Simplifying
i = 0.375n-2s-1x-1